24x^2-7=0

Solution for 24x^2-7=0 equation:

24x^2-7=0

a = 24; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·24·(-7)
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{42}}{2*24}=\frac{0-4\sqrt{42}}{48}
=-\frac{4\sqrt{42}}{48}
=-\frac{\sqrt{42}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{42}}{2*24}=\frac{0+4\sqrt{42}}{48}
=\frac{4\sqrt{42}}{48}
=\frac{\sqrt{42}}{12}
$